If it's not what You are looking for type in the equation solver your own equation and let us solve it.
2b^2-13b+20=0
a = 2; b = -13; c = +20;
Δ = b2-4ac
Δ = -132-4·2·20
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{9}=3$$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-13)-3}{2*2}=\frac{10}{4} =2+1/2 $$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-13)+3}{2*2}=\frac{16}{4} =4 $
| 9(x+5)=3(x-23) | | 7+3x-2=4x | | 5x+3(x÷4)=28 | | 90=3x(5)/(3)-6 | | (x-4)/(x+4)=2/9 | | 0.4(b)=12 | | 3p-6=5p | | 4/4x=9/4 | | (x+4)(x+4+3x)=152 | | 5d-12=7d | | 7(x-3)=2x-2 | | 12=22-5d | | (-7x)+(-6)+(-23x)=180 | | 5x+10=x+48 | | 2=z/9-3 | | 4/3q+8=12 | | 3x-23+90=180 | | (5x+1)+(14x)+(4x-5)=180 | | 1/3c+10=12 | | 5+4x-5x=9 | | x/8-22=20 | | 2y-4(y+1)=-(5y+6)+y | | X^2-9x=120 | | 7x-11=10x | | 8y=24y | | 4y-3=9y | | -5x+52=11x-44 | | 5w=2w=1 | | 25=v+129/8 | | 40=15x+100 | | 60(5x-20)=90 | | 5/3y+6=4 |